Yuliana Tahir: Mulok

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/ 24 = IIIIIII/IIIIIIII/IIIIIIII = IP 2^32-n

=2^32-24

=2⁸

=256

∑ = IP – 2

= 256 – 2

= 254

/25=IIIIIIII/IIIIIIII/IIIIIIII/I0000000 = IP 2^{32 – n}

= 2^{32
– 26}

= 2⁷

= 128

∑ = IP -2

= 128 – 2

= 126

/26= IIIIIIII/IIIIIIII/IIIIIIII/II000000 = IP 2 ^{23 – n}

= 2 ^32-26

= 2⁶

= 64

∑ = IP – 2

= 128- 2

= 126

/27= IIIIIIII/IIIIIIII/IIIIIIII/III00000= IP^{23 – n}

= 2^32-27

= 2 ⁵

= 32

∑ = IP – 2

= 32 – 2

= 30

/28= IIIIIIII/IIIIIIII/IIIIIIII/IIII0000 = = IP^{23 – n}

= 2^32-28

= 2⁴

= 16

∑ = IP – 2

= 16 – 2

= 14

/29= IIIIIIII/IIIIIIII/IIIIIIII/IIIII000 = = IP^{23 – n}

= 2^32-29

= 2³

= 8

∑ = IP – 2

= 8 – 2

= 6

/30= IIIIIIII/IIIIIIII/IIIIIIII/IIIIII00 = IP^{23 – n}

= 2^32-30

= 2²

= 4

∑ = IP – 2

= 4 – 2

= 2

Laman

Rabu, 12 September 2012

Mulok

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